Pybite challenge 128 Strptime and strftime

Author: sksehdev

days/01-03-datetimes/code/PyBites128.py

@@ -0,0 +1,33 @@
+from datetime import datetime
+
+THIS_YEAR = 2018
+
+
+def years_ago(date):
+    """Receives a date string of 'DD MMM, YYYY', for example: 8 Aug, 2015
+       Convert this date str to a datetime object (use strptime).
+       Then extract the year from the obtained datetime object and subtract
+       it from the THIS_YEAR constant above, returning the int difference.
+       So in this example you would get: 2018 - 2015 = 3"""
+    date_time = datetime.strptime(date.replace(",", ""), "%d %b %Y")
+    diff_year = THIS_YEAR - date_time.year
+    return diff_year
+    #pass
+
+
+def convert_eu_to_us_date(date):
+    """Receives a date string in European format of dd/mm/yyyy, e.g. 11/03/2002
+       Convert it to an American date: mm/dd/yyyy (in this case 03/11/2002).
+       To enforce the use of datetime's strptime / strftime (over slicing)
+       the tests check if a ValueError is raised for invalid day/month/year
+       ranges (no need to code this, datetime does this out of the box)"""
+
+    eu_date = datetime.strptime(date.replace("/" , " "), "%d  %m  %Y")
+
+
+    us_date = eu_date.strftime("%m") + "/" + eu_date.strftime("%d") + "/" + eu_date.strftime("%Y")
+
+    return us_date
+
+print(convert_eu_to_us_date('11/03/2002'))
+