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feat: add solutions to lc problems: No.2668,2669
* No.2668.Find Latest Salaries * No.2669.Count Artist Occurrences On Spotify Ranking List
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6 files changed

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solution/2600-2699/2668.Find Latest Salaries/README.md

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@@ -80,7 +80,19 @@ Each row contains employees details and their yearly salaries, however, some of
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```sql
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# Write your MySQL query statement below
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SELECT
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emp_id,
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firstname,
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lastname,
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max( salary ) AS salary,
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department_id
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FROM
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Salary
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GROUP BY
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emp_id
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ORDER BY
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emp_id;
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```
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<!-- tabs:end -->

solution/2600-2699/2668.Find Latest Salaries/README_EN.md

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### **SQL**
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```sql
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# Write your MySQL query statement below
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SELECT
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emp_id,
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firstname,
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lastname,
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max( salary ) AS salary,
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department_id
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FROM
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Salary
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GROUP BY
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emp_id
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ORDER BY
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emp_id;
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```
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<!-- tabs:end -->
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# Write your MySQL query statement below
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SELECT
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emp_id,
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firstname,
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lastname,
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max( salary ) AS salary,
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department_id
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FROM
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Salary
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GROUP BY
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emp_id
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ORDER BY
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emp_id;

solution/2600-2699/2669.Count Artist Occurrences On Spotify Ranking List/README.md

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@@ -64,7 +64,17 @@ Each row contains an id, track_name, and artist.
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```sql
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# Write your MySQL query statement below
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SELECT
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artist,
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count( 1 ) AS occurrences
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FROM
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Spotify
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GROUP BY
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artist
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ORDER BY
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occurrences DESC,
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artist;
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```
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<!-- tabs:end -->

solution/2600-2699/2669.Count Artist Occurrences On Spotify Ranking List/README_EN.md

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### **SQL**
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```sql
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# Write your MySQL query statement below
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SELECT
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artist,
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count( 1 ) AS occurrences
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FROM
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Spotify
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GROUP BY
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artist
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ORDER BY
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occurrences DESC,
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artist;
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```
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<!-- tabs:end -->
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# Write your MySQL query statement below
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SELECT
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artist,
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count( 1 ) AS occurrences
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FROM
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Spotify
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GROUP BY
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artist
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ORDER BY
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occurrences DESC,
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artist;

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