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| 1 | +#include <iostream> |
| 2 | +#include <vector> |
| 3 | + |
| 4 | +/** |
| 5 | + * Merge two sub-arrays of arr[] |
| 6 | + * - First sub-array is arr[left..mid] |
| 7 | + * - Second sub-array is arr[mid+1..right] |
| 8 | + * |
| 9 | + * @param arr The array to be sorted |
| 10 | + * @param left The left index of the first sub-array |
| 11 | + * @param mid The right index of the first sub-array |
| 12 | + * @param right The right index of the second sub-array |
| 13 | + */ |
| 14 | + |
| 15 | +void merge(std::vector<int>& arr, int left, int mid, int right) { |
| 16 | + |
| 17 | + int n1 = mid - left + 1; // size of the first sub-array. |
| 18 | + int n2 = right - mid; // size of the second sub-array. |
| 19 | + |
| 20 | + // create temporary arrays to hold the data |
| 21 | + std::vector<int> leftSubarray(n1); |
| 22 | + std::vector<int> rightSubarray(n2); |
| 23 | + |
| 24 | + // copy data to temporary arrays leftSubarray[] and rightSubarray[] |
| 25 | + for (int i = 0; i < n1; i++) { |
| 26 | + leftSubarray[i] = arr[left + i]; |
| 27 | + } |
| 28 | + for (int j = 0; j < n2; j++) { |
| 29 | + rightSubarray[j] = arr[mid + 1 + j]; |
| 30 | + } |
| 31 | + |
| 32 | + // merge the two sub-arrays back into the original array arr[] |
| 33 | + int i = 0, j = 0, k = left; |
| 34 | + |
| 35 | + while (i < n1 && j < n2) { |
| 36 | + if (leftSubarray[i] <= rightSubarray[j]) { |
| 37 | + arr[k] = leftSubarray[i]; |
| 38 | + i++; |
| 39 | + } |
| 40 | + else { |
| 41 | + arr[k] = rightSubarray[j]; |
| 42 | + j++; |
| 43 | + } |
| 44 | + k++; |
| 45 | + } |
| 46 | + |
| 47 | + // copy the remaining elements of leftSubarray[], if any |
| 48 | + while (i < n1) { |
| 49 | + arr[k] = leftSubarray[i]; |
| 50 | + i++; |
| 51 | + k++; |
| 52 | + } |
| 53 | + |
| 54 | + // copy the remaining elements of rightSubarray[], if any |
| 55 | + while (j < n2) { |
| 56 | + arr[k] = rightSubarray[j]; |
| 57 | + j++; |
| 58 | + k++; |
| 59 | + } |
| 60 | +} |
| 61 | + |
| 62 | + |
| 63 | + |
| 64 | +/** |
| 65 | + * Merge Sort algorithm |
| 66 | + * |
| 67 | + * @param arr The array to be sorted |
| 68 | + * @param left The left index of the sub-array to be sorted |
| 69 | + * @param right The right index of the sub-array to be sorted |
| 70 | + */ |
| 71 | + |
| 72 | +void mergeSort(std::vector<int>& arr, int left, int right) { |
| 73 | + if (left < right) { |
| 74 | + |
| 75 | + int mid = left + (right - left) / 2; // calculate the middle index |
| 76 | + |
| 77 | + // sort the first and second halves |
| 78 | + mergeSort(arr, left, mid); |
| 79 | + mergeSort(arr, mid + 1, right); |
| 80 | + |
| 81 | + // merge the sorted halves |
| 82 | + merge(arr, left, mid, right); |
| 83 | + } |
| 84 | +} |
| 85 | + |
| 86 | +int main() { |
| 87 | + |
| 88 | + std::vector<int> arr = {12, 11, 13, 5, 6, 7, 9, 4, 10, 9, 11, 1, 11}; |
| 89 | + |
| 90 | + int arrSize = arr.size(); |
| 91 | + |
| 92 | + std::cout << "Original array: "; |
| 93 | + for (int num : arr) { |
| 94 | + std::cout << num << " "; |
| 95 | + } |
| 96 | + std::cout << std::endl; |
| 97 | + |
| 98 | + mergeSort(arr, 0, arrSize - 1); |
| 99 | + |
| 100 | + std::cout << "Sorted array: "; |
| 101 | + for (int num : arr) { |
| 102 | + std::cout << num << " "; |
| 103 | + } |
| 104 | + std::cout << std::endl; |
| 105 | + |
| 106 | + return 0; |
| 107 | +} |
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