17 first step

Author: JavaProgrammerLB

17.py

@@ -1,5 +1,55 @@
+import http.cookiejar, urllib.request, urllib.parse
+import bz2
+import http.cookies
+
+
 def main():
-    pass
+    cookie_jar = http.cookiejar.CookieJar()
+    opener = urllib.request.build_opener(urllib.request.HTTPCookieProcessor(cookie_jar))
+    ary = []
+    next_number = open_url(cookie_jar, opener, "12345", ary)
+    while True:
+        if int(next_number) > 0:
+            next_number = open_url(cookie_jar, opener, next_number, ary)
+        else:
+            break
+    encoded_string = "".join(ary)
+    print("ary length is {}".format(len(ary)))
+    print("bs is {}", encoded_string)
+    password = bz2.decompress(str.encode(encoded_string, "latin1"))
+    print("pw is {}".format(password))
+
+
+
+def open_url(cookie_jar, opener, number, ary):
+    url_base = "http://www.pythonchallenge.com/pc/def/linkedlist.php?busynothing="
+    next_number = request_url(cookie_jar, opener, url_base + number, ary)
+    return next_number
+
+
+def request_url(cookie_jar, opener, url, ary):
+    response = opener.open(url)
+    for item in cookie_jar:
+        print("{} {}".format(item.name, item.value))
+        value = item.value
+        b = urllib.parse.unquote_plus(value, "latin1")
+        ary.append(b)
+    print("ary is {}".format(ary))
+    data = response.read()
+    ary = data.decode()
+    next_number = find_next_number(ary)
+    return next_number
+
+
+def find_next_number(doc):
+    flag = "and the next busynothing is "
+    length = len(flag)
+    if flag in doc:
+        index = doc.index(flag)
+    else:
+        return "-1"
+    number = doc[index + length:]
+    return number
 
 
 if __name__ == "__main__":