Add solution 620 [sql]

mod
order by

Author: yanglbme

README.md

@@ -52,6 +52,7 @@ Complete [solutions](https://github.com/doocs/leetcode/tree/master/solution) to
 | 595 | [Big Countries](https://github.com/doocs/leetcode/tree/master/solution/595.Big%20Countries) | `SQL` |
 | 596 | [Classes More Than 5 Students](https://github.com/doocs/leetcode/tree/master/solution/596.Classes%20More%20Than%205%20Students) | `SQL` |
 | 605 | [Can Place Flowers](https://github.com/doocs/leetcode/tree/master/solution/605.Can%20Place%20Flowers) | `Array` |
+| 620 | [Not Boring Movies](https://github.com/doocs/leetcode/tree/master/solution/620.Not%20Boring%20Movies) | `SQL` |
 | 627 | [Swap Salary](https://github.com/doocs/leetcode/tree/master/solution/627.Swap%20Salary) | `SQL` |
 | 695 | [Max Area of Island](https://github.com/doocs/leetcode/tree/master/solution/695.Max%20Area%20of%20Island) | `Array`, `Depth-first Search` |
 | 703 | [Kth Largest Element in a Stream](https://github.com/doocs/leetcode/tree/master/solution/703.Kth%20Largest%20Element%20in%20a%20Stream) | `Heap` |

solution/620.Not Boring Movies/README.md

@@ -0,0 +1,55 @@
+## 有趣的电影
+### 题目描述
+
+
+某城市开了一家新的电影院，吸引了很多人过来看电影。该电影院特别注意用户体验，专门有个 LED显示板做电影推荐，上面公布着影评和相关电影描述。
+
+作为该电影院的信息部主管，您需要编写一个 SQL查询，找出所有影片描述为**非** `boring` (不无聊) 的并且 **id 为奇数** 的影片，结果请按等级 `rating` 排列。
+
+ 
+
+例如，下表 `cinema`:
+```
++---------+-----------+--------------+-----------+
+|   id    | movie     |  description |  rating   |
++---------+-----------+--------------+-----------+
+|   1     | War       |   great 3D   |   8.9     |
+|   2     | Science   |   fiction    |   8.5     |
+|   3     | irish     |   boring     |   6.2     |
+|   4     | Ice song  |   Fantacy    |   8.6     |
+|   5     | House card|   Interesting|   9.1     |
++---------+-----------+--------------+-----------+
+```
+
+对于上面的例子，则正确的输出是为：
+```
++---------+-----------+--------------+-----------+
+|   id    | movie     |  description |  rating   |
++---------+-----------+--------------+-----------+
+|   5     | House card|   Interesting|   9.1     |
+|   1     | War       |   great 3D   |   8.9     |
++---------+-----------+--------------+-----------+
+```
+
+### 解法
+简单查询即可。
+
+```sql
+# Write your MySQL query statement below
+
+select id, movie, description, rating
+from cinema
+where description != 'boring' and mod(id, 2) = 1
+order by rating desc;
+
+```
+
+#### Input
+```json
+{"headers":{"cinema":["id", "movie", "description", "rating"]},"rows":{"cinema":[[1, "War", "great 3D", 8.9], [2, "Science", "fiction", 8.5], [3, "irish", "boring", 6.2], [4, "Ice song", "Fantacy", 8.6], [5, "House card", "Interesting", 9.1]]}}
+```
+
+#### Output
+```json
+{"headers":["id","movie","description","rating"],"values":[[5,"House card","Interesting",9.1],[1,"War","great 3D",8.9]]}
+```