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update solution 002 Solution.js [JavaScript] #45
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Original file line number | Diff line number | Diff line change |
---|---|---|
@@ -0,0 +1,36 @@ | ||
/** | ||
* Definition for singly-linked list. | ||
* function ListNode(val) { | ||
* this.val = val; | ||
* this.next = null; | ||
* } | ||
*/ | ||
/** | ||
* @param {ListNode} l1 | ||
* @param {ListNode} l2 | ||
* @return {ListNode} | ||
*/ | ||
var addTwoNumbers = function(l1, l2) { | ||
var c1 = l1,c2 = l2,c3,l3,carry = 0; | ||
while(c1||c2||carry){ | ||
var v1 = 0,v2 = 0; | ||
if(c1){ | ||
v1 = c1.val; | ||
c1 = c1.next; | ||
} | ||
if(c2){ | ||
v2 = c2.val; | ||
c2 = c2.next; | ||
} | ||
var sum = v1 + v2 + carry; | ||
carry = (sum - sum%10)/10; | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. e.g. carry = (sum - sum % 10) / 10; There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 已修改 |
||
if(!c3){ | ||
l3 = new ListNode(sum%10); | ||
c3 = l3; | ||
}else{ | ||
c3.next = new ListNode(sum%10); | ||
c3 = c3.next; | ||
} | ||
} | ||
return l3; | ||
} |
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代码写得不是很规范噢,适当的空格是必要的~
e.g.
咱们刷题练 Coding 能力,也要争取写出规范的 code 哈~
代码我先
merge
啦,上面是我的一点小小建议😁~There was a problem hiding this comment.
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接受指教,已修改,规范代码很重要